Reverse a Number (JavaScript)
Reverse a Number
Reversing a number means taking its digits and arranging them in reverse order. For example, reversing 123 gives 321. This is a common logical programming problem that helps to practice arithmetic operations and loop control.
Understanding the Concept
The core idea involves extracting the last digit of the number, appending it to a reversed number, and then removing that last digit from the original number until the original number becomes zero. This process typically uses the modulo operator (%) to get the last digit and integer division (Math.floor()) to remove it.
Common Approaches
1. Using a while loop (Iterative Method):
This is the most common and explicit way to reverse a number digit by digit.
Explanation:
reversedNumis initialized to 0.- The
whileloop continues as long asoriginalNumis greater than 0. lastDigit = originalNum % 10;extracts the rightmost digit.reversedNum = reversedNum * 10 + lastDigit;builds the reversed number. Multiplying by 10 shifts existing digits to the left.originalNum = Math.floor(originalNum / 10);removes the rightmost digit fromoriginalNum.- Special handling for negative numbers: reverse the absolute value and then apply the negative sign back.
2. Converting to String and Reversing (Simplified Method):
This method leverages string manipulation functions available in JavaScript, often leading to more concise code, especially for positive integers.
Explanation:
- The number is converted to its absolute value string representation.
split('')converts the string into an array of characters.reverse()reverses the order of elements in the array.join('')concatenates the array elements back into a string.- Finally,
Number()converts the reversed string back to a number. - The original sign is reapplied.
Key Takeaways
- Modulo and Division: Essential for digit-by-digit processing of numbers.
- Type Conversion: Converting between numbers and strings can simplify certain problems.
- Handling Edge Cases: Consider negative numbers and numbers ending in zero (e.g., reversing 120 should yield 21, not 021, which
Number()handles correctly). - Efficiency: The iterative method (Method 1) is generally more efficient for very large numbers as it avoids string conversions, though for typical integer sizes, the string method is often clear enough.